BCCI have announced the same squad.
The Board of Control for Cricket in India has announced the 12-man squad for the second Test match against Windies. The Indian board has announced the same squad as it was for the first Test match. Thus, Shardul Thakur is expected to be the 12th man. Thakur can get his chance if Virat Kohli decides to rest Mohammed Shami or Umesh Yadav.
Therefore, Mayank Agarwal has once again missed out on his place in the playing XI. There were reports that the Karnataka batsman might make his place in the final XI. KL Rahul had scored a duck in the first match and thus he was expected to be dropped.
However, the Indian team has decided to stay with KL Rahul. Furthermore, Mohammed Siraj also could not find his place. Siraj has impressed with his bowling while playing for the India A.
Meanwhile, Prithvi Shaw will get another chance to open with innings with KL Rahul. Shaw had impressed on his debut as he had scored a fine hundred. Thus, he was able to get the Player of the match award.
On the other hand, Ajinkya Rahane had got off to a start in the previous Test match. However, he could not carry on with his innings to make a substantial score. Thus, the Indian deputy will like to get his confidence back before the tour of Australia.
Cheteshwar Pujara had scored a fine 86 in the previous Test match. Therefore, Pujara will like to continue with his good form. Meanwhile, Virat Kohli, Ravindra Jadeja and Rishabh Pant had all impressed with the bat. Furthermore, there were good performances from Kuldeep Yadav and Ravichandran Ashwin with the ball.
Here is India’s 12-man squad for the second Test match:
— BCCI (@BCCI) October 11, 2018